dbv_copy() messing memory
dbv_copy() has the pointer, not the pointed memory, as the copy target. This results in pointers pointing to random address.
There's no current users for dbv_copy(), but #48798 will be one.
dbv_copy() has the pointer, not the pointed memory, as the copy target. This results in pointers pointing to random address.
There's no current users for dbv_copy(), but #48798 will be one.